code segment assume cs:code,ds:data main: mov ax,data mov ds,ax mov cl,100 mov ax,0 again: inc ax add sum,ax dec cl jnz again
mov ax,sum sub ax, 13bah mov sum, ax mov cl,4 shr ax,cl ;take middle 4 bits and ax,000fh
add ax,30h
mov dl, al mov ah, 2 int 21h
mov ax,sum and ax,000fh ;take upper 4 bits add ax,30h
mov dl, al mov ah, 2 int 21h
mov ah,4Ch;终止当前程序并返回调用程序 int 21h;
code ends end main
最新评论