专注于互联网--专注于架构

最新标签
网站地图
文章索引
Rss订阅
select a.id,a.name,a.scorefrom temp a,(select name,max(score) as max_score from temp group by name) bwhere a.name =b.nameand a.score=b.max_score [阅读全文] [PDF]
1 共1条 分1页