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首页 »VB教程 » vb字符串包含:字符串与二进制互相转化(不包含汉字)-vb教程 »正文

vb字符串包含:字符串与二进制互相转化(不包含汉字)-vb教程

来源: 发布时间:星期四, 2008年9月25日 浏览:104次 评论:0
进制与字符的互换,是由于我要做DES加密程序的需要才设计的
现在把我的源程序发布:

先建立一个工程
在框架上画
两个textbox,命名为text1,text2
两个commandbutton, 命名为command1,command1
其他定义自己去该吧!

rem 此程序由Qthinker制作,免费发布,可以修改,请保留此信息
Option Base 1
Private Function byte2bit(s As String) As String
Dim i As Integer, j As Integer, k As Integer, ilen As Integer
Dim by() As String
Dim b() As Integer
ilen = Len(s)
ReDim by(ilen)
ReDim b(ilen / 8)
For k = 1 To ilen
by(k) = Mid$(s, k, 1)
Next k

For i = 1 To (ilen / 8)
If by(1 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H80
Else
b(i) = b(i) And &H7F
End If
If by(2 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H40
Else
b(i) = b(i) And &HBF
End If
If by(3 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H20
Else
b(i) = b(i) And &HDF
End If
If by(4 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H10
Else
b(i) = b(i) And &HEF
End If
If by(5 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H8
Else
b(i) = b(i) And &HF7

End If
If by(6 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H4
Else
b(i) = b(i) And &HFB
End If
If by(7 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or &H2
Else
b(i) = b(i) And &HFD
End If
If by(8 + 8 * (i - 1)) = \"1\" Then
b(i) = b(i) Or \"1\"
Else
b(i) = b(i) And &HFE
End If
byte2bit = byte2bit & Chr$(b(i))

Next i
End Function
Private Function bit2byte(s As String) As String
Dim s2 As String
Dim x As String
Dim i As Integer, k As Integer
Dim ilen As Integer

ilen = Len(s)
Dim b()
Dim s1()
ReDim s1(ilen)
ReDim b(ilen * 8)
s2 = \"\"
For i = 1 To ilen
x = Mid$(s, i, 1)
s1(i) = Asc(x)

If s1(i) And &H80 Then
b(1 + 8 * (i - 1)) = 1
Else
b(1 + 8 * (i - 1)) = 0
End If

If s1(i) And &H40 Then
b(2 + 8 * (i - 1)) = 1
Else
b(2 + 8 * (i - 1)) = 0
End If

If s1(i) And &H20 Then
b(3 + 8 * (i - 1)) = 1
Else
b(3 + 8 * (i - 1)) = 0
End If

If s1(i) And &H10 Then
b(4 + 8 * (i - 1)) = 1
Else
b(4 + 8 * (i - 1)) = 0
End If


If s1(i) And &H8 Then
b(5 + 8 * (i - 1)) = 1
Else
b(5 + 8 * (i - 1)) = 0
End If

If s1(i) And &H4 Then
b(6 + 8 * (i - 1)) = 1
Else
b(6 + 8 * (i - 1)) = 0
End If

If s1(i) And &H2 Then
b(7 + 8 * (i - 1)) = 1
Else
b(7 + 8 * (i - 1)) = 0
End If

If s1(i) And \"1\" Then
b(8 + 8 * (i - 1)) = 1
Else
b(8 + 8 * (i - 1)) = 0
End If

Next i

For k = 1 To ilen * 8
s2 = s2 & b(k)
If k Mod 8 = 0 Then
s2 = s2
End If
Next k
bit2byte = s2
End Function

Private Sub Command1_Click()
Dim s As String
Dim s2 As String
s = Text1.Text
s2 = bit2byte(s)
Text2.Text = s2
End Sub

Private Sub Command2_Click()
Dim s As String
Dim s1 As String
s = Text2.Text
s1 = byte2bit(s)
Text2.Text = s1
End Sub


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